Ncert Solutions For Class 6 Maths Chapter 7 Fractions Ex 7.4 Ncert Solutions For Class 6 Maths Chapter 7 Exercise 7.4 Ncert Class 6 Maths Chapter 7 Exercise 7.4 Class 6 Maths Ncert Solutions Chapter 7 Exercise 7.4 Ncert Solutions For Class 6 Maths Chapter 7 Fractions Exercise 7.4 Ncert Maths Class 6 Chapter 7 Exercise 7.4 Answers Class 6th Maths Ex 7.4 Class 6 Maths Fraction Exercise 7.4

NCERT Solutions for Class 6 Maths Chapter 7 Fractions Ex 7.4

Question 1.
Write shaded portion as a fraction. Arrange them in ascending and descending order using correct sign ‘<‘, ‘=’, ‘>’ between the fraction:
(a)

(b)


appropriate signs between the fractions  given

Solution:

(i) In ascending order, these are

(ii) In descending order, these are

(b)

(i) In ascending order, these are

(ii) In descending order, these are

(c)

Question 2.
Compare the fractions and put an appropriate sign.

Solution :

Question 3.
Make five more such pairs and make appropriate signs.

Question 4.
Look at the figures and write ‘<’ or ‘>’, ‘=’ between the pairs of fractions.
Solution :


Make five more such problems and solve them with your friends.
Solution:

For the remaining part, please try yourself.

Question 5.
How quickly can you do this? Fill appropriate sign (<, =,>)

Solution :


Question 6.
The following fractions represent just three different numbers. Separate them into three groups of equivalent fractions, by changing each one to its simplest form.

Solution :


Question 7.
Find answers to the following. Write and indicate how you solved them.

Solution :
(a) Equivalent fraction of 59 are

Equivalent fraction of 45 are

(b) Equivalent fraction of 916 are

Question 8.
Ila reads 25 pages of a book containing 100 pages. Lalita reads 12 of the same book. Who read less?

Question 9.
Rafiq exercised for 36 of an hour, while 6 Rohit exercised for 34 of an hour. Who exercised for a longer time?
Solution :
∴ 34 > 36
∴ Rohit exercised for a longer time.

Question 10.
In class A of 25 students, 20 passed in first class; in another class B of 30 students, 24 passed in first class. In which class was a greater fraction of students getting first class?
Solution :

Hence, in both the classes the same fraction (45)of total students got first class.

Question 1

Add:

23+16\frac{2}{3} + \frac{1}{6}32​+61​

Solution

Find LCM of 3 and 6:

$\text{LCM}(3,6)=6$

Convert fractions:

23=46\frac{2}{3}=\frac{4}{6}32​=64​

Now add:

46+16=56\frac{4}{6}+\frac{1}{6}=\frac{5}{6}64​+61​=65​

Answer

56\frac{5}{6}65

Question 2

Subtract:

58−14\frac{5}{8} – \frac{1}{4}85​−41​

Solution

Find LCM of 8 and 4:

$\text{LCM}(8,4)=8$

Convert:

14=28\frac{1}{4}=\frac{2}{8}41​=82​

Subtract:

58−28=38\frac{5}{8}-\frac{2}{8}=\frac{3}{8}85​−82​=83​

Answer

38\frac{3}{8}83

Question 3

Add:

35+215\frac{3}{5} + \frac{2}{15}53​+152​

Solution

Find LCM of 5 and 15:

$\text{LCM}(5,15)=15$

Convert:

35=915\frac{3}{5}=\frac{9}{15}53​=159​

Add:

915+215=1115\frac{9}{15}+\frac{2}{15}=\frac{11}{15}159​+152​=1511​

Answer

1115\frac{11}{15}1511

Question 4

Subtract:

712−13\frac{7}{12} – \frac{1}{3}127​−31​

Solution

Find LCM of 12 and 3:

$\text{LCM}(12,3)=12$

Convert:

13=412\frac{1}{3}=\frac{4}{12}31​=124​

Subtract:

712−412=312\frac{7}{12}-\frac{4}{12}=\frac{3}{12}127​−124​=123​

Simplify:

14\frac{1}{4}41​

Answer

14\frac{1}{4}41​