# NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.4

Ncert Solutions For Class 6 Maths Chapter 14 Practical Geometry Ex 14.4 Practical Geometry Exercise 14.4  Ncert Solutions For Class 6 Maths Chapter 14 Practical Geometry Ex 14.4 Chapter 14 Practical Geometry Class 6 Chapter 14 Maths Chapter 14 Class 6 Maths Maths Class 6 Chapter 14 Maths Chapter 14 Class 6 Ncert Maths Class 6 Chapter 14 Ncert Solutions For Class 6 Maths Chapter 14 Practical Geometry Class 6 Maths Chapter 14 Practical Geometry Ex 14.4 Class 6 Maths Ncert Solutions

## NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.4

Question 1.
Draw any line segment AB¯¯¯¯¯¯¯¯ . Mark any point M on it. Through M draw a perpendicular to AB¯¯¯¯¯¯¯¯. (use ruler and compasses).
Solution :
Step 1. Given a point M on any line AB¯¯¯¯¯¯¯¯. Step 2. With M as centre and a convenient radius, construct a part circle (arc) intersecting the line segment AB¯¯¯¯¯¯¯¯ at two points C and D.
Step 3. With C and D as centres and a radius greater than CM, construct two arcs which cut each other at N.
Step 4. Join MN¯¯¯¯¯¯¯¯¯¯. Then MN¯¯¯¯¯¯¯¯¯¯ is perpendicular to AB¯¯¯¯¯¯¯¯ at M, i.e., MN¯¯¯¯¯¯¯¯¯¯ AB¯¯¯¯¯¯¯¯.

Question 2.
Draw any’line segment PQ¯¯¯¯¯¯¯¯. Take any point R not on it. Through R draw a perpendicular to PQ¯¯¯¯¯¯¯¯. (use ruler and set-square).
Solution :
Step 1. Let PQ¯¯¯¯¯¯¯¯ be the given line segment and R be a point not on it. Step 2. Place a set-square on PQ¯¯¯¯¯¯¯¯ such that one arm of the right angle aligns along PQ¯¯¯¯¯¯¯¯.
Step 3. Place a ruler along the edge opposite of the right angle.
Step 4. Hold the ruler fixed. Slide the set-square along the ruler all the point R touches the arm of the set-square.
Step 5. Join RS along the edge through R, meeting PQ¯¯¯¯¯¯¯¯ at S. Now RS¯¯¯¯¯¯¯ PQ¯¯¯¯¯¯¯¯.

Question 3.
Draw a line l and a point X on it. Through X, draw a line segment XY¯¯¯¯¯¯¯¯ perpendicular to l. Now draw a perpendicular to XY at Y. (use ruler and compasses)
Solution :
Step 1. Given a point X on a line l.
Step 2. With X as centre and a convenient radius, construct a part circle (arc) intersecting the line l at two points A and B.
Step 3. With A and B as centres and a radius greater than AX, construct two arcs which cut each other at Y. Step 4. Join XY¯¯¯¯¯¯¯¯. Then XY¯¯¯¯¯¯¯¯ is perpendicular to l atX, i.e., XY¯¯¯¯¯¯¯¯ l.

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