# NCERT Solutions for Class 6 Maths Chapter 4 Basic Geometrical Ideas Ex 4.1

Which is very important for all the students of class six to understand matriculation and we have explained the geometry of chapter 4 of NCERT class six mathematics in a very good way for the students. Solved in this way, I have tried my best to explain the geometry to the students in visual form, we have started all the NCERT questions in the solution of NCERT through diagram

## NCERT Solutions for Class 6 Maths Chapter 4 Basic Geometrical Ideas Ex 4.1

Question 1.
Use the figure to name:
(a) Five points
(b) A line
(c) Four rays
(d) Five line segments.
Solution :
(a) O, B, C. D, E Question 2.
Name the line given in all possible (twelve) ways, choosing only two letters at a time from the four given.
Solution :  Question 3.
Use the figure to name:
(a) The line containing point E.
(b) The line passing through A.
(c) The line on which O lies
(d) Two pairs of intersecting lines. Solution :
(a) AE←→, etc.
(b) AE←→, etc.
(c) CO←→orOC←→
(d) CO,←→−AE←→;AE←→,EF←→.

Question 4.
How many lines can pass through
(a) one given point?
(b) two given points?
Solution :
(a) Countless lines can pass through one given point.
(b) One and only one line can pass through two given points.

Question 5.
Draw a rough figure and label suitably in each of the following cases :
(a) Point P lies on AB¯
(b) XY←→ and PQ←→ intersect at M.
(c) Line contains E and F but not D.
(d) Op¯ and OQ¯ meet at O.
Solution :
(a) (b) (c) (d) Question 6.
Consider the following figure of line MN¯ Say whether following statements are true or false in context of the given figure.
(a) Q, M, O, N, P are points on the line MN¯
(b) M, O, N are points on a line segment MN¯.
(c) M and N are end points of line segment MN¯. (d) O and N are end points of line segment OP¯.
(e) M is one of the end points of line segment QO¯.
(f) M is point on ray OP−→−.
(g) Ray OP−→− is different from ray QP−→−.
(h) Ray OP−→− is same as ray OM−→−.
(i) Ray OM−→− is not opposite to ray OP−→−.
(j) O is not an initial point of OP−→−.
(k) N is the initial point of NP−→− and NM−→−.
Solution :
(a) True
(b) True
(c) True
(d) False
(e) False
(f) False
(g) True
(h) False
(i) False
(j) False
(k) True.

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