NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.2

Ncert Solutions For Class 6 Maths Chapter 14 Practical Geometry Ex 14.2 Practical Geometry Exercise 14.2 Ncert Solutions For Class 6 Maths Chapter 14 Practical Geometry Ex 14.2 Chapter 14 Practical Geometry Class 6 Chapter 14 Maths Chapter 14 Class 6 Maths Maths Class 6 Chapter 14 Maths Chapter 14 Class 6 Ncert Maths Class 6 Chapter 14 Ncert Solutions For Class 6 Maths Chapter 14 Practical Geometry Class 6 Maths Chapter 14 Practical Geometry Ex 14.2 Class 6 Maths Ncert Solutions

NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry Ex 14.2

Question 1.
Draw a line segment of length 7.3 cm. using a ruler.
Solution :
Using ruler, we mark two points A and B which are 7.3 cm apart. Join A and B and get AB. AB¯¯¯¯¯¯¯¯ is a line segment of length 7.3 cm.
NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry 7

Question 2.
Construct a line segment of length 5.6 cm using ruler and compasses.
NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry 8
Solution :
Step 1. Draw a line l. Mak a point A on line l.
Step 2. Place the compasses pointer on the ∠ero mark on the ruler. Open it to place the pencil point upto the 5.6 cm mark.
Step 3. Without changing the opening of the compasses, place the pointer on A and swing an arc to cut / at B.
Step 4. AB is a line segment of required length.

Question 3.
Construct AB¯¯¯¯¯¯¯¯ of length 7.8 cm. From this cut off AC¯¯¯¯¯¯¯¯ of length 4.7 cm. Measure BC¯¯¯¯¯¯¯¯.
Solution :
Steps of Construction
Step 1. Draw a line l. Mark a point A on line l.
Step 2. Place the compasses pointer on the ∠ero mark on the ruler. Open it to place the pencil point upto the 7.8 cm mark.
NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry 9
Step 3. Without changing the opening of the compasses, place the pointer on A and swing an arc to cut / at B.
Step 4. AB¯¯¯¯¯¯¯¯ is a line segment of length 7.8 cm.
Step 5. Place the compasses pointer on the ∠ero mark on the ruler. Open it to place the pencil point upto 4.7 cm mark.
Step 6. Without changing the opening of the compasses, place the pointer on A and swing an arc to cut / at C.
Step 7. AC¯¯¯¯¯¯¯¯ is a line segment of length 4.7 cm. On measurement. BC¯¯¯¯¯¯¯¯ =3.1 cm.

Question 4.
Given AB¯¯¯¯¯¯¯¯ of length 3.9 cm, construct PQ¯¯¯¯¯¯¯¯ such that the length of PQ¯¯¯¯¯¯¯¯ is twice that of AB Verify by measurement.
NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry 10
(Hint : Construct PX¯¯¯¯¯¯¯¯ such that length of PX = length of AB¯¯¯¯¯¯¯¯; then cut off XQ¯¯¯¯¯¯¯¯ such that XQ¯¯¯¯¯¯¯¯ also has the length of AB¯¯¯¯¯¯¯¯).
Solution :
Steps of Construction
Step 1. Draw a line I. Mark a point P on line l.
Step 2. Place the compasses pointer on the A mark of the given line segment AB¯¯¯¯¯¯¯¯ . Open it to place the pencil point upto B mark of the given line segment AB¯¯¯¯¯¯¯¯.
NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry 11
Step 3. Without changing the opening of the compasses, place the pointer on P and swing an arc to cut l at X.
Step 4. Again without changing the opening of the compasses place the compasses pointer on the X mark of line / and swing an arc to cut / at Q.
Step 5. PQ¯¯¯¯¯¯¯¯ is a line segment of length twice that of AB¯¯¯¯¯¯¯¯. Please verify yourself by measurement.

Question 5.
Given AB¯¯¯¯¯¯¯¯ of length 7.3 cm and CD¯¯¯¯¯¯¯¯ of length 3.4 cm, construct a line segment XY¯¯¯¯¯¯¯¯ such that the length of XY¯¯¯¯¯¯¯¯ is equal to the difference between the lengths of AB¯¯¯¯¯¯¯¯ and CD¯¯¯¯¯¯¯¯ . Verify by measurement.
Solution :
Steps of Construction
Step 1. Draw a line l. Mark a point X on line l.
Step 2. Place the compasses pointer on the A mark of the given line segment AB¯¯¯¯¯¯¯¯. Open it to place the pencil point upto B mark of the given line segment AB¯¯¯¯¯¯¯¯.
Step 3. Without changing the opening of the compasses, place the pointer of compasses on X and swing an arc to cut / at ∠.
Step 4. Place the compasses pointer on the C mark of the given line segment CD¯¯¯¯¯¯¯¯. Open it to place the pencil point upto D mark of the given line segment CD¯¯¯¯¯¯¯¯.
Step 5. Without changing the opening of the compasses, place the pointer of compasses on ∠ and swing an arc towards X to cut l at Y.
Step 6. XY¯¯¯¯¯¯¯¯ is a required line segment of length = the difference between the lengths of AB¯¯¯¯¯¯¯¯ and CD¯¯¯¯¯¯¯¯.
NCERT Solutions for Class 6 Maths Chapter 14 Practical Geometry 12

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