NCERT Solutions for Class 6 Maths Chapter 11 Algebra Ex 11.5

Ncert Solutions For Class 6 Maths Chapter 11 Algebra Ex 11.5 Ncert Solutions For Class 6 Maths Chapter 11 Algebra Exercise 11.5 Class 6 Maths Chapter 11 Algebra Exercise 11.5 Class 6 Chapter 11 Exercise 11.5

NCERT Solutions for Class 6 Maths Chapter 11 Algebra Ex 11.5

Question 1.
State which of the following are equations (with a variable). Give reason for your answer. Identify the variable from the equations with a variable.
(a) 17 = x + 7
(b) (t-7)> 5
(c) 42 =2
(d) (7 x 3)-19 = 8
(e) 5 x 4 – 8 =2x
(f) x – 2 =0
(g) 2m<30
(h) 2n+1=11
(i) 7=(11 x 5) -(12x 4)
(j) 7=(11×2)+p
(k) 20=5y
(l) latex]\frac { 3q }{ 2 } [/latex]<5
(m) z+12>24
(n) 20-(10-5)=3×5
(o) 7-x =5
Solution.
NCERT Solutions for Class 6 Maths Chapter 11 Algebra 18
Question 2.
Complete the entries in the third column of the table.
NCERT Solutions for Class 6 Maths Chapter 11 Algebra 19
NCERT Solutions for Class 6 Maths Chapter 11 Algebra 19
Solution.
(a) Yes
(b) Yes
(c) No
(d) No
(e) No
(f) Yes
(g) No
(h) No
(i)  Yes
(j) Yes
(k) No
(l) No
(m) No
(n) No
(o) No
(p) No
(q) Yes

Question 3.
Pick out the solution from the values given bracket next to each equation. Show that the values do not satisfy the equation.
(a) 5m – 60 (10, 5, 12, 15)
(b) n + 12 = 20 (12, 8, 20, 0)
(c) p-5 = 5 (0, 10, 5,-5)
(d) q2 = 7 (7, 2, 10, 14)
(e) r-4- 0 (4, – 4. 8, 0)
(f) x + 4 – . y (-2, 0, 2. 4)
Solution.
(a) Solution is 12
For m = 10
L.H.S. = 5 x 10 = 50 which is not equal to R.H.S.
For m = 5
L.H.S. = 5 x 5 = 25 which is not equal to R.H.S.
For m = 15
L.H.S. = 5 x 15 = 75 which is not equal to R.H.S.

(b) Solution is 8
For n = 12

L.H.S. = 12+12
= 24 which is not equal to R.H.S.
For n = 20
L.H.S. = 20+12
= 32 which is not equal to R.H.S.
For n =0
L.H.S. = 0+12
= 12 which is not equal to R.H.S.

(c) Solution is 10
For p = 0
L.H.S. = 0 – 5 = – 5 which is not equal to R.H.S.
For p = 5
L.H.S. = 5-5 = 0 which is not equal to R.H.S.
For p = – 5
L.H.S. = – 5 – 5 = – 10 which is not equal to R.H.S.

(d) Solution is 14
For g = 7
L.H.S. = q2 which is not equal to R.H.S.
For q = 2
L.H.S. = 22 = 1 which is not equal to R.H.S.
For q = 10
L.H.S. = 102 = 5 which is not equal to R.H.S.

(e) Solution is 4
For r = – 4
L.H.S. = -4-4
= – 8 which is not equal to R.H.S.
For r = 8
L.H.S. = 8-4 = 4 which is not equal to R.H.S.
For r = 0
L.H.S. = 0 – 4 = – 4 which is not equal to R.H.S.

(f) Solution is – 2
For x = 0
L.H.S. = 0 + 4 = 4 which is not equal to R.H.S. For x = 2
L.H.S. = 2 + 4 = 6 which is not equal to R.H.S.
For x : = 4
L.H.S. = 4 + 4 = 8 which is not equal to R.H.S.

Question 4.
(a) Complete the table and by inspection of the table find the solution to the equation m + 10 = 16
NCERT Solutions for Class 6 Maths Chapter 11 Algebra 20
(b) Complete the table and by inspection of the table find the solution to the equation 5t = 35
NCERT Solutions for Class 6 Maths Chapter 11 Algebra 21
(c) Complete the table and find using the table the solution of the equation z/3 = 4
NCERT Solutions for Class 6 Maths Chapter 11 Algebra 22
(d) Complete the table and find the solution to the equation m-7=3
NCERT Solutions for Class 6 Maths Chapter 11 Algebra 23
Solution.
NCERT Solutions for Class 6 Maths Chapter 11 Algebra 24

Question 5.
Solve the following riddles, you may yourself construct such riddles.
Who am I?
(i)
 Go round a square
Counting every corner
Thrice and no more!
Add the count to me
To get exactly thirty four!
NCERT Solutions for Class 6 Maths Chapter 11 Algebra 25

(ii) For each day of the week
Make an account from me
If you make no mistake
You will get twenty three!

(iii) I am a special number
Take away from me a six!
A whole cricket team
You will still be able to fix!
NCERT Solutions for Class 6 Maths Chapter 11 Algebra 26

(iv) Tell me who I am
I shall give a pretty clue!
You will get me back
If you take me out of twenty-two!
Solution.
(i) Let the required number be x.
Number of corners of the square = 4
Number obtained on counting every comer thrice = 4 x 3=12
According to the question, x + 12 = 34 ⇒ x = 34 -12 = 22
Hence, I am 22.

(ii) Let the required number be x.
Number of players in a cricket team = 11
According to the question.
x – 6 = 11  ⇒ x =11+6=17
Hence, lam 17.

(iii) Let the required number be v.
Number of days of a week = 7
According to the question.
x + 7 = 23    ⇒ x = 23-7 =16
Hence, lam 16.

(iv) Let the required number be x.
According to the question.
22 – x = x ⇒ x + x = 22
2x = 22    ⇒ x = 102 = 11
Hence, lam 11.