{"id":5986,"date":"2025-06-09T11:49:14","date_gmt":"2025-06-09T11:49:14","guid":{"rendered":"https:\/\/thecompanyboy.com\/?p=5986"},"modified":"2025-06-09T11:49:14","modified_gmt":"2025-06-09T11:49:14","slug":"rs-aggarwal-quantitative-aptitude-pdf-download-pipes-cisterns-and","status":"publish","type":"post","link":"https:\/\/www.reilsolar.com\/drive\/rs-aggarwal-quantitative-aptitude-pdf-download-pipes-cisterns-and\/","title":{"rendered":"RS Aggarwal Quantitative Aptitude PDF Free Download: PIPES AND CISTERNS"},"content":{"rendered":"

PIPES AND CISTERNS<\/strong><\/h1>\n

IMPORTANT FACTS <\/u><\/strong>AND FORMULAE<\/u><\/strong><\/h2>\n
    \n
  1. Inlet:<\/strong> A pipe connected with a tank or a cistern or a reservoir, that fills it, is known as an inlet.<\/li>\n<\/ol>\n

    Outlet:<\/strong> A pipe connected with a tank or a cistern or a reservoir, emptying it, is<\/p>\n

    known as an outlet.<\/p>\n

      \n
    1. (i) If a pipe can fill a tank in x hours, then : part filled in 1 hour = 1\/x<\/li>\n<\/ol>\n

      (ii) If a pipe can empty a full tank in y <\/em>hours, then : part emptied in 1 hour = 1\/y<\/p>\n

      (iii) If a pipe can .fill a tank in x hours and another pipe can empty the full tank in y hours\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 (where y> x), <\/em>then on opening both the pipes, the net part filled in 1 hour = (1\/x)-(1\/y)<\/p>\n

      \u00a0 \u00a0\u00a0\u00a0\u00a0(iv) If a pipe can fill a tank in x hours and another pipe can empty the full tank in y hours (where x > y), <\/em>then on opening both the pipes, the net part emptied in 1 hour = (1\/y)-(1\/x)<\/p>\n

      SOLVED EXAMPLES<\/h1>\n

      \u00a0\u00a0 Ex. 1:Two pipes <\/strong>A and B can fill a tank <\/strong>in 36 bours and 46 bours respectively. <\/strong>If both\u00a0 the pipes are opened simultaneously, bow mucb time will be taken to fill the<\/strong><\/p>\n

      tank?<\/strong><\/p>\n

      Sol:<\/strong> Part filled by A in 1 hour = (1\/36);<\/p>\n

      \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Part filled by B in 1 hour = (1\/45);<\/p>\n

      \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Part filled by (A + B) In 1 hour =(1\/36)+(1\/45)=(9\/180)=(1\/20)<\/p>\n

      \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Hence, both the pipes together will fill the tank in 20 hours.<\/p>\n

      Ex. 2: Two pipes can fill a tank in 10hours and 12 hours respectively while a third, pipe empties the full tank in 20 hours. If all the three pipes operate simultaneously, in how much time will the tank be filled?<\/strong><\/p>\n

      Sol:<\/strong> Net part filled In 1 hour =(1\/10)+(1\/12)-(1\/20)=(8\/60)=(2\/15).<\/p>\n

      \u00a0\u00a0\u00a0\u00a0\u00a0 The tank will be full in 15\/2 <\/u>hrs = 7 hrs 30 min.<\/p>\n

      Ex. 3: If two pipes function simultaneously, tbe reservoir will <\/strong>be filled in 12 hours. One pipe fills the reservoir 10 hours faster than tbe otber. How many hours <\/strong>does it take the second pipe to fill the reservoir?<\/strong><\/p>\n

      Sol<\/strong>:let the reservoir be filled by first pipe in x hours.<\/p>\n

      \u00a0\u00a0\u00a0\u00a0\u00a0 Then ,second pipe fill it in (x+10)hrs.<\/p>\n

      \u00a0\u00a0\u00a0\u00a0\u00a0 Therefore (1\/x)+(1\/x+10)=(1\/12)\u00a0\u00a0 \u00f3(x+10+x)\/(x(x+10))=(1\/12).<\/p>\n

      \u00a0 \u00f3 x^2 \u201314x-120=0\u00a0 \u00f3 (x-20)(x+6)=0<\/p>\n

      \u00a0\u00a0 \u00f3x=20\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 [neglecting the negative value of x]<\/p>\n

      \u00a0\u00a0\u00a0\u00a0\u00a0 so, the second pipe will take (20+10)hrs. (i.e) 30 hours to fill the reservoir<\/p>\n

      Ex. 4: A cistern has two taps which fill it in 12 minutes and 15minutes respectively. There is also a waste pipe in the cistern. When all the 3 are opened , the empty cistern is full in 20 minutes. How long will the waste pipe take to empty the full cistern?<\/p>\n

      Sol<\/strong>: Workdone by the waste pipe in 1min<\/p>\n

      \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 =(1\/20)-(1\/12)+(1\/15) = -1\/10\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 [negative sign means emptying]<\/p>\n

      \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 therefore the waste pipe will empty the full cistern in 10min<\/p>\n

      Ex. 5: An electric pump can fill a tank in 3 hours. Because <\/strong>of a leak in ,the tank it took 3(1\/2) hours to fill the tank. If the tank is full, how much time will the leak take <\/strong><\/p>\n

      to empty it ?<\/strong><\/p>\n

      Sol<\/strong>: work done by the leak in 1 hour=(1\/3)-(1\/(7\/2))=(1\/3)-(2\/7)=(1\/21).<\/p>\n

      \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \u00a0The leak will empty .the tank in 21 hours.<\/p>\n

      \u00a0Ex. 6. Two pipes can fill a cistern in 14 hours and 16 hours respectively. The pipes <\/strong><\/p>\n

      are opened simultaneously and it is found that due to leakage in the <\/strong>bottom it tooki 32 minutes more to fill the cistern.When the cistern is full, in what time\u00a0 will the leak empty it?<\/strong><\/p>\n

      Sol:<\/strong> Work done by the two pipes in 1 hour =(1\/14)+(1\/16)=(15\/112).<\/p>\n

      \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Time taken by these pipes to fill the tank = (112\/15) hrs = 7 hrs 28 min.<\/p>\n

      \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Due to leakage, time taken = 7 hrs 28 min + 32 min = 8 hrs<\/p>\n

      \u00a0\u00a0\u00a0\u00a0\u00a0 Work done by (two pipes + leak) in 1 hour = (1\/8).<\/p>\n

      \u00a0\u00a0\u00a0\u00a0\u00a0 Work done by the leak m 1 hour =(15\/112)-(1\/8)=(1\/112).<\/p>\n

      \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Leak will empty the full cistern in 112 hours.<\/p>\n

      Ex. 7: Two pipes A and B can fill a tank in 36 min. and 45 min. respectively. A water\u00a0 pipe C can empty the tank in 30 min. First A and B are opened. after 7 min,C is also opened. In how much time, the tank is full?<\/p>\n

      Sol:<\/strong>Part filled in 7 min. = 7*((1\/36)+(1\/45))=(7\/20).<\/p>\n

      \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Remaining part=(1-(7\/20))=(13\/20).<\/p>\n

      \u00a0\u00a0\u00a0\u00a0\u00a0 Net part filled in 1min. when A,B and C are opened=(1\/36)+(1\/45)-(1\/30)=(1\/60).<\/p>\n

      \u00a0\u00a0\u00a0\u00a0\u00a0 Now,(1\/60) part is filled in one minute.<\/p>\n

      \u00a0\u00a0\u00a0\u00a0 (13\/20) part is filled in (60*(13\/20))=39 minutes.<\/p>\n

      \u00a0\u00a0\u00a0\u00a0 Ex.8: Two pipes A,B can fill a tank in 24 min. and 32 min. respectively. If both the pipes are opened simultaneously, after how much time B should be closed so that the tank is full in 18 min.?<\/p>\n

      Sol<\/strong>: let B be closed after x min. then ,<\/p>\n

      \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Part filled by (A+B) in x min. +part filled by\u00a0 A in (18-x)min.=1<\/p>\n

      \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Therefore x*((1\/24)+(1\/32))+(18-x)*(1\/24)=1\u00a0\u00a0 \u00f3 (7x\/96) + ((18-x)\/24)=1.<\/p>\n

      \u00a0\u00a0\u00a0\u00a0\u00a0 \u00f3 7x +4*(18-x)=96.<\/p>\n

      \u00a0\u00a0\u00a0\u00a0\u00a0 Hence, be must be closed after 8 min.<\/p>\n

      I can’t provide a free PDF download of Quantitative Aptitude<\/em> by R.S. Aggarwal, as it is copyrighted material. However, here are some ways to access the Pipes and Cisterns<\/strong> chapter legally:<\/p>\n

      Legal Ways to Access the Book:<\/h3>\n
        \n
      1. Official Publisher Website<\/strong> \u2013 Check S. Chand Publishing for official copies.<\/li>\n
      2. Google Books & Amazon Kindle<\/strong> \u2013 Some sections may be available for preview.<\/li>\n
      3. Library Services<\/strong> \u2013 Public or university libraries may have a digital or physical copy.<\/li>\n
      4. Educational Platforms<\/strong> \u2013 Websites like Unacademy, BYJU\u2019S, and Gradeup provide explanations and practice problems on this topic.<\/li>\n<\/ol>\n

        Need Help with Pipes and Cisterns?<\/h3>\n

        I can explain concepts, provide formulas, and give you practice problems with solutions. Let me know what you need!<\/p>\n

        RS Aggarwal Quantitative Aptitude PDF Free Download: PIPES AND CISTERNS<\/a><\/h3>\n

         <\/p>\n

         <\/p>\n

         <\/p>\n","protected":false},"excerpt":{"rendered":"

        PIPES AND CISTERNS IMPORTANT FACTS AND FORMULAE Inlet: A pipe connected with a tank or a cistern or a reservoir, that fills it, is known as an inlet. Outlet: A pipe connected with a tank or a cistern or a reservoir, emptying it, is known as an outlet. (i) If a pipe can fill a […]<\/p>\n","protected":false},"author":41,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[126,127],"tags":[],"class_list":["post-5986","post","type-post","status-publish","format-standard","hentry","category-rs-aggarwal-quantitative-aptitude","category-rs-aggarwal-quantitative-aptitude-pdf"],"_links":{"self":[{"href":"https:\/\/www.reilsolar.com\/drive\/wp-json\/wp\/v2\/posts\/5986","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.reilsolar.com\/drive\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.reilsolar.com\/drive\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.reilsolar.com\/drive\/wp-json\/wp\/v2\/users\/41"}],"replies":[{"embeddable":true,"href":"https:\/\/www.reilsolar.com\/drive\/wp-json\/wp\/v2\/comments?post=5986"}],"version-history":[{"count":0,"href":"https:\/\/www.reilsolar.com\/drive\/wp-json\/wp\/v2\/posts\/5986\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.reilsolar.com\/drive\/wp-json\/wp\/v2\/media?parent=5986"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.reilsolar.com\/drive\/wp-json\/wp\/v2\/categories?post=5986"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.reilsolar.com\/drive\/wp-json\/wp\/v2\/tags?post=5986"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}