{"id":5902,"date":"2025-06-09T07:53:44","date_gmt":"2025-06-09T07:53:44","guid":{"rendered":"https:\/\/thecompanyboy.com\/?p=5902"},"modified":"2025-06-09T07:53:44","modified_gmt":"2025-06-09T07:53:44","slug":"rs-aggarwal-quantitative-aptitude-pdf-download-problems-ages-on","status":"publish","type":"post","link":"https:\/\/www.reilsolar.com\/drive\/rs-aggarwal-quantitative-aptitude-pdf-download-problems-ages-on\/","title":{"rendered":"RS Aggarwal Quantitative Aptitude PDF Free download: PROBLEMS ON AGES"},"content":{"rendered":"<h1 style=\"text-align: center\"><strong> PROBLEMS ON AGES<\/strong><\/h1>\n<p><strong>\u00a0<\/strong><strong>Ex. 1. Rajeev&#8217;s <\/strong><strong>age after <\/strong><strong>15 years <\/strong><strong>will <\/strong><strong>be 5 times his age 5 <\/strong><strong>years <\/strong><strong>back. <\/strong><strong>What is the <\/strong><\/p>\n<p><strong>present age of Rajeev <\/strong><strong>?<\/strong>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 (Hotel Management,2002)<\/p>\n<p>&nbsp;<\/p>\n<p>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Sol. Let Rajeev&#8217;s present age be x years. Then,<\/p>\n<p>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Rajeev&#8217;s age after 15 years = (x + 15) years.<\/p>\n<p>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Rajeev&#8217;s age 5 years back = (x &#8211; 5) years.<\/p>\n<p>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 :.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 x + 15 = 5 (x &#8211; 5) \u00f3x + 15 = 5x &#8211; 25\u00a0\u00a0 \u00f3\u00a0\u00a0 4x = 40 \u00f3\u00a0 x = 10.<\/p>\n<p>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Hence, Rajeev&#8217;s present age = 10 years.<\/p>\n<p><strong>Ex. 2. <em>The ages <\/em>of <em>two persons differ by <\/em>16 <em>years. <\/em>If 6 <em>years ago, the <\/em><\/strong><strong><em>elder <\/em><\/strong><strong>\u00a0one be <\/strong><\/p>\n<p><strong>3 <em>times as old as the younger <\/em>one, <em>find their present ages.<\/em><\/strong> \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 (A.A.O. Exam,2003)<\/p>\n<p>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Sol. Let the age of the younger person be x years.<\/p>\n<p>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Then, age of the elder person = (x + 16) years.<\/p>\n<p>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 :.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 3 (x &#8211; 6) = (x + 16 &#8211; 6)\u00a0 \u00f3\u00a0 3x -18 = x + 10\u00a0\u00a0 \u00f3\u00a0 2x = 28 \u00f3 x = 14.<\/p>\n<p>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Hence, their present ages are 14 years and 30 years.<\/p>\n<p><strong>\u00a0<\/strong><strong>Ex. 3. <em>The product <\/em>of <em>the ages <\/em>of <em>Ankit and Nikita is 240. <\/em>If <em>twice the <\/em>age of Nikita<\/strong><\/p>\n<p><strong><em>is more than Ankit&#8217;s age by <\/em><\/strong><strong>4 <em>years, what is Nikita&#8217;s age?<\/em>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 <\/strong>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 (S.B.I.P.O,1999)<\/p>\n<p>Sol. Let Ankit&#8217;s age be x years. Then, Nikita&#8217;s age = 240\/xyears.<\/p>\n<p>\\ 2 \u00b4 (240 \/x ) \u2013 x = 4 \u00f3 480 \u2013 x<sup>2<\/sup> = 4x \u00f3 x<sup>2<\/sup> + 4x \u2013 480 = 0<\/p>\n<p>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \u00f3 ( x+24)(x-20) = 0 \u00f3 x = 20.\u00a0<\/p>\n<p>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Hence, Nikita&#8217;s age = <u>(22_0) <\/u>years = 12 years.\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 1<\/p>\n<p><strong>Ex. 4. <em>The present age <\/em>of a <em>father is <\/em>3 <em>years more than three times the <\/em>age of his <em>son. Three years hence, father&#8217;s age will be 10 years more than twice the <\/em>age <em>of the <\/em>son. <em>Find the present age <\/em>of <em>the <\/em>father<em>.<\/em>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 .\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 (S.S.C, 2003)<\/strong><\/p>\n<p><strong>\u00a0\u00a0\u00a0\u00a0\u00a0 <\/strong>Sol. Let the son&#8217;s present age be x years. Then, father&#8217;s present age = <em>(3x <\/em>+ 3) years<\/p>\n<p>\u00a0\u00a0\u00a0\u00a0\u00a0 \\<em>\u00a0\u00a0\u00a0\u00a0\u00a0 (3x <\/em>+ 3 + 3) = 2 (x + 3) + 10 \u00f3\u00a0 3x + 6 = 2x + 16\u00a0\u00a0\u00a0 \u00f3\u00a0\u00a0\u00a0\u00a0 x = 10.<\/p>\n<p>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Hence, father&#8217;s present age = <em>(3x <\/em>+ 3) = ((3 \u00b4 10) + 3) years = 33 years.<\/p>\n<p><strong>Ex. 5. R<em>ohit was <\/em>4 <em>times as old as his son <\/em>8 <em>years ago. After <\/em>8 <em>years, Rohit will be<\/em><\/strong><\/p>\n<p><strong><em>twice as old as his son. What are their present ages?<\/em><\/strong><\/p>\n<p>\u00a0\u00a0\u00a0\u00a0\u00a0 Sol. Let son&#8217;s age 8 years ago be x years. Then, Rohit&#8217;s age 8 years ago = 4x years.<\/p>\n<p>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Son&#8217;s age after 8 years = (x + 8) + 8 = (x + 16) years.<\/p>\n<p>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Rohit&#8217;s age after 8 years = <em>(4x <\/em>+ 8) + 8 = <em>(4x+ <\/em>16) years.<\/p>\n<p>\u00a0\u00a0\u00a0\u00a0\u00a0 \\ 2 (x + 16) = 4x + 16 \u00f3 2x = 16 \u00f3 x = 8.<\/p>\n<p>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Hence, son&#8217;s &#8216;present age = (x + 8) = 16 years.<\/p>\n<p>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Rohit&#8217;s present age = <em>(4x <\/em>+ 8) = 40 years.<\/p>\n<p><strong>Ex. 6. One <\/strong><strong><em>year ago, the ratio <\/em><\/strong><strong>of <em>Gaurav\u2019s and Sachin\u2019s age was <\/em>6: 7 <em>respectively.<\/em><\/strong><\/p>\n<p><strong><em>Four years hence, this ratio would become <\/em><\/strong><strong>7: 8. <em>How old is Sa chin <\/em>?<\/strong><\/p>\n<p>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 (NABARD, 2002)<\/p>\n<p>Sol:<\/p>\n<p>. Let Gaurav&#8217;s and Sachin&#8217;s ages one year ago be 6x and 7x years respectively. Then, Gaurav&#8217;s age<\/p>\n<p>\u00a0 4 years hence = <em>(6x <\/em>+ 1) + 4 = <em>(6x <\/em>+ 5) years.<\/p>\n<p>Sachin&#8217;s age 4 years hence = <em>(7x <\/em>+ 1) + 4 = <em>(7x <\/em>+ 5) years.<\/p>\n<p><u>\u00a0<\/u><u>6x+5 <\/u>\u00a0= <u>7 <\/u>\u00a0\u00f3 8(6x+5) = 7 <em>(7x <\/em>+ 5)\u00a0 \u00f3 <em>48x <\/em>+ 40 = <em>49x <\/em>+ 35\u00a0 \u00f3 <em>x <\/em>= 5.<\/p>\n<p>7x+5\u00a0\u00a0\u00a0\u00a0 8<\/p>\n<p>\u00a0\u00a0\u00a0\u00a0\u00a0 Hence, Sachin&#8217;s present age = <em>(7x <\/em>+ 1) = 36 years.<\/p>\n<p>,<strong>7. <em>Abhay\u2019s age after six years will be three-seventh <\/em>of <em>his fathers age. Ten years <\/em><\/strong><strong>ago the <\/strong><strong><em>ratio <\/em><\/strong><strong>of <em>their ages was 1 <\/em>: 5. <em>What is Abhay\u2019s father&#8217;s age <\/em>at <em>present?<\/em><\/strong><\/p>\n<p>Sol. Let the ages of Abhay and his father 10 years ago be x and 5x years respectively. Then,<\/p>\n<p>\u00a0\u00a0\u00a0\u00a0\u00a0 Abhay&#8217;s age after 6 years = (x + 10) + 6 = (x + 16) years.<\/p>\n<p>\u00a0\u00a0\u00a0\u00a0\u00a0 Father&#8217;s age after 6 years = <em>(5x <\/em>+ 10) + 6 = <em>(5x <\/em>+ 16) years.<\/p>\n<p><em>\\x <\/em>+ 16) = \u00a0<u>3<\/u> <em>(5x <\/em>+ 16)\u00a0 \u00f3 7 <em>(x <\/em>+ 16) = 3 <em>(5x <\/em>+ 16)\u00a0 \u00f3 <em>7x <\/em>+ 112 = <em>15x <\/em>+ 48<\/p>\n<p>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 7\u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0<\/p>\n<p>\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \u00f3\u00a0 <em>8x <\/em>= 64\u00a0\u00a0 \u00f3 \u00a0x = 8.<\/p>\n<p>Hence, Abhay&#8217;s father&#8217;s present age = <em>(5x <\/em>+ 10) = 50 years.<\/p>\n<p><span style=\"color: #ffffff\">rs aggarwal quantitative aptitude problems on ages quantitative aptitude for competitive examinations rs aggarwal competition book rs aggarwal quantitative aptitude for competitive examinations rs agarwal aptitude rs aggarwal aptitude book age problem questions age problems with solutions and answers pdf rs aggarwal aptitude age related problems problems on ages questions and answers pdf age problems practice problems on ages tricks rs aggarwal quantitative aptitude quora rs agarwal aptitude book problems on ages with solutions pdf problems on ages with solutions age aptitude questions ages aptitude problems on ages formulas s chand quantitative aptitude rs aggarwal quantitative aptitude book ages aptitude questions aptitude book rs aggarwal price problems on ages pdf<\/span><\/p>\n<p>&#8220;Problems on Ages&#8221; is a key topic in R.S. Aggarwal&#8217;s &#8220;Quantitative Aptitude&#8221; book, typically covered in Chapter 8. This chapter provides a variety of problems to help understand and solve age-related questions commonly found in competitive exams.<\/p>\n<p>While the complete book is available for purchase through various retailers, accessing specific chapters for free can be challenging due to copyright restrictions. However, some educational platforms and forums may offer excerpts or summaries of specific chapters. For instance, TheCompanyBoy provides a discussion on &#8220;Problems on Ages&#8221; from R.S. Aggarwal&#8217;s book.<\/p>\n<p>Please ensure that any resources you access comply with copyright laws. Supporting authors by purchasing their work not only ensures you receive accurate and high-quality content but also encourages the creation of more educational materials.<\/p>\n<h3>RS Aggarwal Quantitative Aptitude PDF Free download: PROBLEMS ON AGES<\/h3>\n<p>.<\/p>\n","protected":false},"excerpt":{"rendered":"<p>PROBLEMS ON AGES \u00a0Ex. 1. Rajeev&#8217;s age after 15 years will be 5 times his age 5 years back. What is the present age of Rajeev ?\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 (Hotel Management,2002) &nbsp; \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Sol. Let Rajeev&#8217;s present age be x years. Then, \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Rajeev&#8217;s age after 15 years = (x + 15) years. \u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Rajeev&#8217;s age [&hellip;]<\/p>\n","protected":false},"author":41,"featured_media":0,"comment_status":"closed","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"footnotes":""},"categories":[127],"tags":[2661,2662,2663,2664,2665,2666,2667,2668,2669,2670,2671,2672,2673,2674,2675,2241,2412,2413,2414,2415,2417,1923,2418,2337,2676,2419],"class_list":["post-5902","post","type-post","status-publish","format-standard","hentry","category-rs-aggarwal-quantitative-aptitude-pdf","tag-age-aptitude-questions","tag-age-problem-questions","tag-age-problems-practice","tag-age-problems-with-solutions-and-answers-pdf","tag-age-related-problems","tag-ages-aptitude","tag-ages-aptitude-questions","tag-aptitude-book-rs-aggarwal-price","tag-problems-on-ages","tag-problems-on-ages-formulas","tag-problems-on-ages-pdf","tag-problems-on-ages-questions-and-answers-pdf","tag-problems-on-ages-tricks","tag-problems-on-ages-with-solutions","tag-problems-on-ages-with-solutions-pdf","tag-quantitative-aptitude-for-competitive-examinations","tag-rs-agarwal-aptitude","tag-rs-agarwal-aptitude-book","tag-rs-aggarwal-aptitude","tag-rs-aggarwal-aptitude-book","tag-rs-aggarwal-competition-book","tag-rs-aggarwal-quantitative-aptitude","tag-rs-aggarwal-quantitative-aptitude-book","tag-rs-aggarwal-quantitative-aptitude-for-competitive-examinations","tag-rs-aggarwal-quantitative-aptitude-quora","tag-s-chand-quantitative-aptitude"],"_links":{"self":[{"href":"https:\/\/www.reilsolar.com\/drive\/wp-json\/wp\/v2\/posts\/5902","targetHints":{"allow":["GET"]}}],"collection":[{"href":"https:\/\/www.reilsolar.com\/drive\/wp-json\/wp\/v2\/posts"}],"about":[{"href":"https:\/\/www.reilsolar.com\/drive\/wp-json\/wp\/v2\/types\/post"}],"author":[{"embeddable":true,"href":"https:\/\/www.reilsolar.com\/drive\/wp-json\/wp\/v2\/users\/41"}],"replies":[{"embeddable":true,"href":"https:\/\/www.reilsolar.com\/drive\/wp-json\/wp\/v2\/comments?post=5902"}],"version-history":[{"count":0,"href":"https:\/\/www.reilsolar.com\/drive\/wp-json\/wp\/v2\/posts\/5902\/revisions"}],"wp:attachment":[{"href":"https:\/\/www.reilsolar.com\/drive\/wp-json\/wp\/v2\/media?parent=5902"}],"wp:term":[{"taxonomy":"category","embeddable":true,"href":"https:\/\/www.reilsolar.com\/drive\/wp-json\/wp\/v2\/categories?post=5902"},{"taxonomy":"post_tag","embeddable":true,"href":"https:\/\/www.reilsolar.com\/drive\/wp-json\/wp\/v2\/tags?post=5902"}],"curies":[{"name":"wp","href":"https:\/\/api.w.org\/{rel}","templated":true}]}}